JEE Advanced 2025 — Marks vs Rank Complete Table
Complete marks to CRL rank conversion table for JEE Advanced 2025 based on official IIT Kanpur published data. Total 33,859 candidates in the Common Rank List (CRL). Paper 1 + Paper 2 combined out of 360 marks.
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Frequently Asked Questions
What is the marks vs rank relationship in JEE Advanced 2025?
In JEE Advanced 2025 (IIT Kanpur): 332 marks = rank 1, 278 marks = rank 101, 250 marks = rank 301, 200 marks = rank 1201, 180 marks = rank 2001, 150 marks = rank 4401, 120 marks = rank 9901, 74 marks = rank 33859 (last CRL rank). Total 33,859 candidates appeared in the Common Rank List (CRL).
How many marks are needed to get rank under 1000 in JEE Advanced 2025?
To get a CRL rank under 1000 in JEE Advanced 2025, you need approximately 205 marks or more (out of 360). The top 1000 rank cutoff was around 205–208 marks based on official IIT Kanpur data.
What is the minimum marks to qualify JEE Advanced 2025?
The minimum qualifying marks for JEE Advanced 2025 are: General category — 74 marks, EWS — 66 marks, OBC-NCL — 66 marks, SC — 37 marks, ST — 37 marks. These are aggregate marks out of 360. Candidates also need to meet subject-wise minimums.
How is JEE Advanced rank calculated?
JEE Advanced rank (CRL) is calculated based on the aggregate marks scored across both Paper 1 and Paper 2 (combined out of 360). Ties are resolved using a specific rule: higher positive marks wins; if equal, higher Mathematics marks wins; if still tied, both get the same rank. Reserved category candidates are ranked separately on their category rank lists.
How JEE Advanced Scoring Works
JEE Advanced 2025 had two papers (Paper 1 and Paper 2), each of 180 marks, totalling 360 marks. Both papers are mandatory. Your CRL rank is based on combined Paper 1 + Paper 2 marks. Each paper has 3 sections: Physics, Chemistry, and Mathematics with varying mark schemes (full, partial, and negative marking depending on question type).
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